Difference between revisions of "Solução: Problema da simplificação das frações (Bruno Barbosa)"

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Line 24: Line 24:
 
while(n || m){  
 
while(n || m){  
 
   
 
   
if(!n || !m)
+
if(!n || !m){
printf("%d %d\n", n, m);
+
 
 +
if(n != 0)
 +
printf("%d %d\n", n/n, m);
 +
if(m != 0)
 +
printf("%d %d\n", n, m/m);
 +
}
 
   
 
   
 
else
 
else

Latest revision as of 18:53, 12 June 2009

#include <stdio.h>
 
int analisaImprime(int num, int x, int y);
 
int analisaImprime(int i, int x, int y){
 
	while((x%i!=0)||(y%i!=0)){
		i--;
	}
	if((x%i == 0)&&(y%i==0))
		printf("%d %d\n", x/i, y/i);
 
	else
		printf("%d %d\n", x, y);
}
 
int main(){
 
	int n, m;
	scanf("%d %d", &n, &m);
 
	while(n || m){ 
 
		if(!n || !m){
 
			if(n != 0)
				printf("%d %d\n", n/n, m);
			if(m != 0)
				printf("%d %d\n", n, m/m);
		}
 
		else
			analisaImprime(n, n, m);  
 
		scanf("%d %d", &n, &m);
	}
}